Advertisements
Advertisements
प्रश्न
A cross between a normal couple resulted in a son who was haemophilic and a normal daughter. In course of time, when the daughter was married to a normal man, to their surprise, the grandson was also haemophilic.
(a) Represent this cross in the form of a pedigree chart. Give the genotypes of the daughter and her husband.
(b) Write the conclusion you draw of the inheritance pattern of this disease.
उत्तर
(a)
Genotype of daughter- XXh
Genotype of husband- XY
(b) Haemophilia is a sex-linked recessive disease. Here, it is transmitted from the carrier female to the sons. From the above pedigree chart, it can be observed that the disease is being transmitted from the carrier female to her daughter (carrier) and son (affected). The carrier daughter transmits this disease to the grandson. This pattern of inheritance is called crisscross inheritance.
APPEARS IN
संबंधित प्रश्न
Answer the following question.
Name the type of cross that would help to find the genotype of a pea plant bearing violet flowers.
Give an example of complete linkage.
What was Morgan's observation when he hybridized yellow bodied white eyed female Drosophila to brown bodied red eyed male Drosophila and inter-crossed their progeny?
The genetic map distance between two genes located on the same chromosome can be analyzed by calculating ____________.
The phenomenon of ____________ is universal and it is necessary for the natural selection, because it increases the chances of variation.
Mendal formulated the law of purity of gametes on the basis of ______.
Which of the following is correct for the condition when plant YyRr is back crossed with the double recessive parent?
Genes located very close to one another on same chromosome tend to be transmitted together and are called as ______.
When the parental gene combine with itself; termed as
Which of the following statement is correct?
