Question

A current of 1 A is drawn by a filament of an electric bulb. Number of electrons passing through a cross-section of the filament in 16 seconds would be roughly:

पर्याय

• 10²⁰

• 10¹⁶

• 10¹⁸

• 10²³

Answer 1

10²⁰

Explanation:

I = `"Q"/"t"`

Q = It

Q = 1 × 16

Q = 16q

Q = ne

n = `"Q"/"e"`

n = `16/(1.6 xx 10^-19)`

n = 10 × 10¹⁹

n = 10²⁰ electrons

∴ The number of electrons flowing is 10²⁰ electrons.