Question

A cyclist with combined mass 80 kg goes around a curved road with a uniform speed 20 m/s. He has to bend inward by an angle `theta` = tan^-1 (0.50) with the vertical. The force of friction acting at the point of contact of tyres and road surface is______.

[g = 10 m/s2 ]

पर्याय

• 300 N

• 400 N

• 800 N

• 250 N

Answer 1

A cyclist with combined mass 80 kg goes around a curved road with a uniform speed 20 m/s. He has to bend inward by an angle `theta` = tan^-1 (0.50) with the vertical. The force of friction acting at the point of contact of tyres and road surface is 400 N.

Explanation:

In order for the cyclist to tum Frictional force = centripetal force

`=> µ"mg" = "m" ("v"^2/"r") = "mg" "v"^2/"rg"`

But `"v"^2/"rg" = tan theta`

`therefore µ"mg" = "mg" tan theta`

`= 80 xx 10 xx 0.5`

= 400N