Question

A cylinder of gas supplied by Bharat Petroleum is assumed to contain 14 kg of butane. If a normal family requires 20,000 kJ of energy per day for cooking, butane gas in the cylinder last for ______ Days. (Δ H_c of C₄ H₁₀ = - 2658 JK per mole)

पर्याय

• 20.69

• 10.05

• 25.06

• 32.06

Answer 1

A cylinder of gas supplied by Bharat Petroleum is assumed to contain 14 kg of butane. If a normal family requires 20,000 kJ of energy per day for cooking, butane gas in the cylinder last for 32.06 Days.

Explanation:

Calorific value of butane `= (Delta "H"_"c")/("mol." " wt.")`

`= 2658/58`

= 45.8 kJ/g

Cylinder consist 14 kg of butane means 14000 g of butane

∴ 1 g gives = 45.8 kJ/g

∴ 14000 g gives = 14000 × 45.8 = 641200 kJ

Family need 20,000 kJ/day

So gas full fill the requirement for `641200/20000` = 32.06 days