Question

A domain in a ferromagnetic substance is in the form of a cube of side length 1 µm. If it contains 6 x 10¹⁰ atoms and each atomic dipole has a dipole moment of 7 x 10^-24 Am², then magnetization of the domain is ____________.

पर्याय

• 4.2 x 10⁵ Am^-1

• 4.2 x 10³ Am^-1

• 4.2 x 10¹² Am^-1

• 4.2 x 10⁹ Am^-1

Answer 1

A domain in a ferromagnetic substance is in the form of a cube of side length 1 µm. If it contains 6 x 10¹⁰ atoms and each atomic dipole has a dipole moment of 7 x 10^-24 Am², then magnetization of the domain is 4.2 x 10⁵ Am^-1.

Explanation:

Number of atoms = 6 x 10¹⁰

Dipole moment of each atom = 7 x 10²⁴ Am²

∴ Total dipole moment = 6 x 10¹⁰ x 7 x 10^-24

= 42 x 10^-14 Am²

Volume of domain= (10^-6)³ = 10^-18 m³

`"Magnetization" = (42 xx 10^-14)/10^-18 = 4.2 xx 10^5  "Am"^-1`