Question

A drop of solution (volume 0.05 ml) contains 3.0 × 10^-6 mole of H⁺. If the rate constant of disappearance of H⁺ is 1.0 × 10⁷ mole l^-1s^-1. It would take for H⁺ in drop to disappear in ______ × 10^-9s.

पर्याय

• 6.00

• 2.00

• 9.00

• 4.00

Answer 1

A drop of solution (volume 0.05 ml) contains 3.0 × 10^-6 mole of H⁺. If the rate constant of disappearance of H⁺ is 1.0 × 10⁷ mole l^-1s^-1. It would take for H⁺ in drop to disappear in 6.00 × 10^-9s.

Explanation:

Concentration of drop = `"Mole"/"volume in ml" xx 1000`

`= (3.0 xx 10^-6)/0.05 xx 1000`

= 0.06 mol L^-1

Disappearance of 10⁷ mol L^–1 takes 1 s

Disappearance of 0.06 mol L^–1 will take

`0.06/10^7 = 6.00 xx 10^-9`s