Question

A ferris wheel with radius 20 m makes 1 revolution in every 10 s. The force exerted by the passenger of weight 55 kg on the seat, when he is at the top of the ferris wheel, is ____________.

पर्याय

• 5.5 kg-wt

• 11 kg-wt

• 22 N

• 44 N

Answer 1

A ferris wheel with radius 20 m makes 1 revolution in every 10 s. The force exerted by the passenger of weight 55 kg on the seat, when he is at the top of the ferris wheel, is 11 kg-wt.

Explanation:

Force exerted by passenger on seat is

`= "mg" - "m"omega^2"r" = "m"("g" - omega^2 "r")`

`= 55 (9.8 - ((2 pi)/10)^2 xx 20)`

`= 55(9.8 - (9.8 xx 4)/5)`

`= 55 xx 9.8 (1 - 4/5)` 

`= 55/5 xx 9.8`

`= 11 xx 9.8`

` = 11  "kg-wt"`