Question

A force F = (10 + 0.5 x) N acts on a particle in the x-direction. The work done by the force in displacing the particle from x = 0 to x = 2 metre is ______.

पर्याय

• 42 J

• 63 J

• 21 J

• 31.5 J

Answer 1

A force F = (10 + 0.5 x) N acts on a particle in the x-direction. The work done by the force in displacing the particle from x = 0 to x = 2 metre is 21 J.

Explanation:

`W=int_0^2Fdx=int_0^2(10+0.5x)dx`

`=[10x+0.5x^2/2]_0^2`

= 21 J