Advertisements
Advertisements
प्रश्न
A force of 30 N acts on a body and moves it through a distance of 5 m in the direction of force. Calculate the work done by the force.
उत्तर
F = 30 N
d= 5m
Work done = w = F × d
W = 30 × 5= 150 J
APPEARS IN
संबंधित प्रश्न
In each of the following a force, F is acting on an object of mass, m. The direction of displacement is from west to east, as shown by the longer arrow. Observe the diagrams carefully and state whether the work done by the force is negative, positive or zero.
An electron emitter must have _____________ work function and ___________ melting point.
State the S.I. unit of energy.
Define 1 joule of energy.
Express joule in terms of erg.
The power of a motor is 40 kW. At what speed can the motor raise a load of 20,000 N?
Find the kinetic energy of a body of mass 1 kg moving with a uniform velocity of 10 m s-1.
In case of negative work, the angle between the force and displacement is :
Choose one or more correct alternatives.
Joule is the unit of ______.
- force
- work
- power
- energy
State the conditions of equilibrium for a rigid body.
What do you mean by a kilo joule?
Complete the following sentences:
The SI unit of work is ....... and of power is .......
Name the type of energy possessed by a
(i) stretched catapult (ii) hot iron
(iii) wound up clock
Fill in the boxe to show the corresponding energy transformation.
Is power a scalar or a vector quantity?