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प्रश्न
A force of F = (5y + 20) `hat"j"` N acts on a particle. The work done by this force when the particle is moved from y = 0 m to y = 10 m is ______ J.
पर्याय
150
450
250
350
MCQ
रिकाम्या जागा भरा
उत्तर
A force of F = (5y + 20) `hat"j"` N acts on a particle. The work done by this force when the particle is moved from y = 0 m to y = 10 m is 450 J.
Explanation:
Given, Force, F = (5y + 20) `hat"j"`
Work done, W = `int`F.dy
⇒ W = `int_0^10(5"y"+20)"dy"`
= `[(5"y")^2/2+20"y"]_0^10`
= `5/2xx100+20xx10`
= 450 J
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