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प्रश्न
A gas ‘A’ reacts with another gas ‘B’ in the presence of a catalyst to give a colourless gas ‘C’. The gas ‘C’ when comes in contact with air produces a brown gas ‘D’. The solution of ‘A’ in water turns red litmus blue. Explain the observations.
उत्तर
As the 'A' turns red litmus blue, it is a base. Now the gas 'A' combines with 'B' in the presence of a catalyst to give colourless gas Nitrogen monoxide. It reacts with oxygen to give brown gas, which is Nitrogen dioxide.
A = \[\ce{NH3}\]
B = \[\ce{O2}\]
C = \[\ce{NO}\]
D = \[\ce{NO2}\]
Catalyst = \[\ce{Pt}\]
Reactions:
With air \[\ce{NO}\] forms → \[\ce{NO2}\] [Brown gas] - gas 'D'
\[\ce{4NH3 + 5O2 ->[Pt 800°C] 4NO↑ + 6H2O + Heat}\]
\[\ce{2NO + O2 -> \underset{(Brown gas)}{2NO2}}\]
\[\ce{NH3}\] in water forms \[\ce{NH4OH}\] which turns red litmus blue.
\[\ce{NH3 + H2O -> NH4OH}\]
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