Question

A gas of 0.5 mole at 300 K expands isothermally from an initial volume of 2.0 litre to a final volume of 6.0 litre. What is the work done by gas?

Answer 1

Given:

Number of moles of gas (n) = 0.5 moles

Temperature (T) = 300 K

Initial Volume (V₁) = 2.0 L = 2.0 × 10⁻³ m³

Final Volume (V₂) = 6.0 L = 6.0 × 10⁻³ m³

Universal Gas Constant (R) = 8.314 J/mol K

W = `nRT ln (V_2/V_1)`

W = `0.5 xx 8.314 xx 300 xx ln(6.0/2.0)`

W = `0.5 xx 8.314 xx 300 xx ln 3`

W = `0.5 xx 8.314 xx 300 xx 1.0986`

W = 1370 J