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प्रश्न
A golfer hits a ball at rest, such that the contact between the ball and golf stick is for 0.1 s. If the golf ball covers a linear distance of 400 m in 2 s, find the magnitude of force applied. Mass of golf ball is 50 g.
उत्तर
Distance covered by ball = 400 m
Time taken = 2 s
Distance 400
∴ Uniform velocity of the ball = `"Distance"/"Time"=400/2` = 200 ms−1
Now initial velocity of the ball = u = 0
Time for which force acts on the ball = t = 0.1 s
Final velocity of the ball after the force stops acting on it
= v = 200 ms−1
Using, v = ut + at
We have, 200 = 0 + a (0.1)
a = `200/0.1` = 2000 ms−2
Mass of the ball = m = 50 g = 0.05 kg
Force acting on the ball = F = ma
F = 0.05 × 2000
F = 100N
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