Advertisements
Advertisements
प्रश्न
A jeweller claims that he makes ornaments of pure gold that has a relative density of 19.3. He sells a bangle weighing 25.25 gf to a person. The clever customer weighs the bangle when immersed in water and finds that it weighs 23.075 gf in water. With the help of suitable calculations, find out whether the ornament is made of pure gold or not.
[Hint : calculate R.D. of material of bangle which comes out to be 11.6].
उत्तर
R.D. of pure gold = 19.3
Weight of bangle in air, W1 = 25.25 gf
Weight of bangle when completely immersed in water W2 = 23.075 gf
R.D. of bangle = `W_1/(W_1 - W_2) xx "R.D. of water"`
R.D. of bangle = `25.25/(25.25 - 23.075) xx 1`
R.D. of bangle = 11.6
The bangle is not made of pure gold as its density is not 19.3.
संबंधित प्रश्न
Assuming the density of air to be 1.295 kg m-3, find the fall in barometric height in mm of Hg at a height of 107 m above the sea level. Take density of mercury = 13.6 × 103 kg m-3.
A bunch of feathers and a stone of the same mass are released simultaneously in air. Which will fall faster and why? How will your observation be different if they are released simultaneously in vacuum?
A body of density ρ sinks in a liquid of density ρL. The densities ρ and ρL are related as :
Define the term density.
A body weighs W gf in air and W1 gf when it is completely immersed in water. Find: (i) Volume of the body, (ii) Upthrust on the body and (iii) Relative density of the material of the body.
The density of water is :
A wooden cube of side 10 cm has mass 700 g. What part of it remains above the water surface while floating vertically on water surface?
If the density of ice is 0.9 g cm-3, then what portion of an iceberg will remain below the surface of water in sea? (Density of sea water = 1.1 g cm-3)
A solid body weighs 2.10 N. in air. Its relative density is 8.4. How much will the body weigh if placed
(1) in water,
(2) in liquid of relative density 1.2?
Select the correct option:
When a body is floating in a liquid:
