मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान इयत्ता ११

A Lady Uses + 1.5 D Glasses to Have Normal Vision from 25 Cm Onwards. She Uses a 20 D Lens as a Simple Microscope to See an Object. - Physics

Advertisements
Advertisements

प्रश्न

A lady uses + 1.5 D glasses to have normal vision from 25 cm onwards. She uses a 20 D lens as a simple microscope to see an object. Find the maximum magnifying power if she uses the microscope (a) together with her glass (b) without the glass. Do the answers suggest that an object can be more clearly seen through a microscope  without using the correcting glasses?

थोडक्यात उत्तर

उत्तर

Given:
The lady uses glasses of +1.5 D to have normal vision from 25 cm onwards.
Least distance of clear vision, D = 25 cm 

Focal length of the glasses, f = `1/(Power) = 1/1.5` m

She should have greater least distance of distinct vision without the glasses.
Take:
u = – 25 cm = - 0.25 m
The lens formula is given by

`1/v -1/u = 1/f`

Putting the values, we get:

`1/v = 1.5 -1/0.25  =2.5`

⇒ v = 0.4 m =40 cm 

Near point without glasses = 40 cm
Focal length of magnifying glass, f = `1/20` = 0.05 m = 5 cm
(a) The maximum magnifying power () if she uses the microscope together with her glass is given by

m = `1+D/f`

Here,
D = 25 cm
f = 5 cm
On substituting the values, we get:

m = 1+`25/5 =6`

(b) Without the glasses, D = 40 cm.

∴ m = `1+D/f = 1 + 40/5 = 9`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 19: Optical Instruments - Exercise [पृष्ठ ४३२]

APPEARS IN

एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
पाठ 19 Optical Instruments
Exercise | Q 23 | पृष्ठ ४३२

संबंधित प्रश्‍न

Explain the basic differences between the construction and working of a telescope and a microscope


A giant refracting telescope has an objective lens of focal length 15 m. If an eye piece of focal length 1.0 cm is used, what is the angular magnification of the telescope ?


Draw a labelled ray diagram showing the formation of a final image by a compound microscope at least distance of distinct vision


Magnifying power of a simple microscope is inversely proportional to the focal length of the lens. What then stops us from using a convex lens of smaller and smaller focal length and achieving greater and greater magnifying power?


When viewing through a compound microscope, our eyes should be positioned not on the eyepiece but a short distance away from it for best viewing. Why? How much should be that short distance between the eye and eyepiece?


How can the resolving power of a compound microscope be increased? Use relevant formula to support your answer.


How is 'limit of resolution' related to resolving power of a microscope ?


A compound microscope uses an objective lens of focal length 4 cm and eyepiece lens of focal length 10 cm. An object is placed at 6 cm from the objective lens. Calculate the magnifying power of the compound microscope. Also calculate the length of the microscope.


Draw the labelled ray diagram for the formation of image by a compound microscope.

Derive the expression for the total magnification of a compound microscope. Explain why both the objective and the eyepiece of a compound microscope must have short focal lengths.


An object is placed at a distance u from a simple microscope of focal length f. The angular magnification obtained depends


Consider the following two statements :-

(A) Line spectra contain information about atoms.

(B) Band spectra contain information about molecules.


The magnifying power of a converging lens used as a simple microscope is `(1+D/f).` A compound microscope is a combination of two such converging lenses. Why don't we have magnifying power `(1+D/f_0)(1+D/f_0)`?In other words, why can the objective not be treated as a simple microscope but the eyepiece can?


An eye can distinguish between two points of an object if they are separated by more than 0.22 mm when the object is placed at 25 cm from the eye. The object is now seen by a compound microscope having a 20 D objective and 10 D eyepiece separated by a distance of 20 cm. The final image is formed at 25 cm from the eye. What is the minimum separation between two points of the object which can now be distinguished?


Draw a neat labelled ray diagram showing the formation of an image at the least distance of distinct vision D by a simple microscope. When the final image is at D, derive an expression for its magnifying power at D. 


compound microscope consists of two convex lenses of focal length 2 cm and 5 cm. When an object is kept at a distance of 2.1 cm from the objective, a virtual and magnified image is fonned 25 cm from the eye piece.  Calculate the magnifying power of the microscope.


A convex lens of a focal length 5 cm is used as a simple microscope. Where should an object be placed so that the image formed by it lies at the least distance of distinct vision (D = 25 cm)?


In the case of a regular prism, in minimum deviation position, the angle made by the refracted ray (inside the prism) with the normal drawn to the refracting surface is ______.


On increasing the focal length of the objective, the magnifying power ______.


A compound microscope consists of two converging lenses. One of them, of smaller aperture and smaller focal length, is called objective and the other of slightly larger aperture and slightly larger focal length is called eye-piece. Both lenses are fitted in a tube with an arrangement to vary the distance between them. A tiny object is placed in front of the objective at a distance slightly greater than its focal length. The objective produces the image of the object which acts as an object for the eye-piece. The eye-piece, in turn, produces the final magnified image.

Which of the following is not correct in the context of a compound microscope?


In a compound microscope an object is placed at a distance of 1.5 cm from the objective of focal length 1.25 cm. If the eye-piece has a focal length of 5 cm and the final image is formed at the near point, find the magnifying power of the microscope.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×