Question

A man goes 80m due east and then 150m due north. How far is he from the starting point?

Answer 1

Let the man starts from point A and goes 80 m due east to B.
Then, from B, he goes 150 m due north to c.  

  

We need to find AC.
In right- angled triangle ABC, we have:  

`AC^2=AB^2+BC^2`  

`AC=sqrt(80^2+150^2)`

`=sqrt(6400+22500)`  

`=sqrt289000` 

`=170 m ` 

Hence, the man is 170 m away from the starting point.