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प्रश्न
A metal M forms a volatile chloride containing 65.5% chlorine. If the density of the chloride relative to hydrogen is 162.5, find the molecular formula of the chloride (M = 56).
उत्तर
% age of M in the chloride = 100 − 65.5 = 34.5
| Element | Mass % age | Atomic mass | Rel. number of atoms | Simplest ratio |
| M | 34.5 | 56 | `34.5/56` = 0.6 | `0.61/0.61` = 1 |
| Cl | 65.5 | 35.5 | `65.5/35.5` = 1.84 | `18.4/0.6` = 3 |
The empirical formula of chloride = MCl3
The empirical formula of mass = 56 + 35.5 × 3
= 162.5 g
Vapour density = 162.5
Molecular density = 2 × vapour density
= 2 × 162.5
= 325.0 g
Molecular Formula = (Empirical formula) × n
and n = `"Molecular mass"/"Empirical formula mass"`
= `325.0/162.5`
= 2
∴ Molecular Formula = (MCl3)2 or M2Cl6
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