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प्रश्न
A mixture of dihydrogen and dioxygen at one bar pressure contains 20% by weight of dihydrogen. Calculate the partial pressure of dihydrogen.
उत्तर
Let the weight of dihydrogen be 20 g and the weight of dioxygen be 80 g.
Then, the number of moles of dihydrogen, `"n"_("H"_2) = 20/2 = 10` and the number of moles of dioxygen, `"n"_("O"_2) = 80/32 = 2.5` moles
Given,
Total pressure of the mixture, `"p"_"total"` = 1 bar
Then, partial pressure of dihydrogen,
`"p"_("H"_2) = "n"_("H"_2)/("n"_("H"_2) + 'n"_("O"_2)) xx "P"_"total"`
`= 10/(10 + 2.5) xx 1`
= 0.8 bar
Hence, the partial pressure of dihydrogen is 0.8 bar.
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