Question

A parallel plate capacitor is charged to 100 × 10^-6 C. Due to radiations, falling from a radiating source, the plate loses charge at the rate of 2 × 10^-7 Cs^-1. The magnitude of displacement current is ______.

पर्याय

• `10^-6` A

• `10^-4` A

• `2 xx 10^-7` A

• `2 xx 10^-7` mCs^-1

Answer 1

A parallel plate capacitor is charged to 100 × 10^-6 C. Due to radiations, falling from a radiating source, the plate loses charge at the rate of 2 × 10^-7 Cs^-1. The magnitude of displacement current is `underlinebb(2 xx 10^-7 "A")`.

Explanation:

Given, rate of loss of charge = `2 xx 10^-7` Cs^-1

The magnitude of displacement current is given by,

`"i"_"d" = "i"_"c" = |("dq")/("dt")| = 2 xx 10^-7` Cs^-1 = `2 xx 10^-7` A

∴ The displacement current is 2 × 10^-7 A.