Question

A particle executing S.H.M. has amplitude 0.01 m and frequency 60 Hz. The maximum acceleration of the particle is ____________.

पर्याय

• `60  pi^2  "m"//"s"^2`

• `88  pi^2  "m"//"s"^2`

• `140  pi^2  "m"//"s"^2`

• `144  pi^2  "m"//"s"^2`

Answer 1

A particle executing S.H.M. has amplitude 0.01 m and frequency 60 Hz. The maximum acceleration of the particle is `144  pi^2  "m"//"s"^2`.

Explanation:

The maximum acceleration of a particle executing S.H.M. is given by,

`"a"_"max" = omega^2 "A"`

`"Since,"  omega = 2 pi"v","therefore we have"`

`"a"_"max" = (2 pi  "v")^2 "A"`

Substituting v = 60 Hz; A = 0.01, we get

`"a"_"max" = 144  pi^2  "ms"^-2`