Question

A particle is dropped from a height H. The de Broglie wavelength of the particle as a function of height is proportional to

पर्याय

• H

• `1//sqrt"H"`

• H° 

• `sqrt"H"`

Answer 1

`1//sqrt"H"`

Explanation - 

de-broglie wavelength `λ = "h"/"mv" = "h"/("m"sqrt(2"gH"))`

∴ wavelength `lambda ∝ 1/sqrt"H"`