Question

A particle is moving in a straight line such that its velocity is increasing at 5 ms^-1 per meter. The acceleration of the particle is ______  ms^-2 at a point where its velocity is 20 ms^-1.

पर्याय

• 100

• 200

• 300

• 400

Answer 1

A particle is moving in a straight line such that its velocity is increasing at 5 ms^-1 per meter. The acceleration of the particle is 100 ms^-2 at a point where its velocity is 20 ms^-1.

Explanation:

`"dv"/"ds"` = 5; As a = `"dV"/"dt" = "dV"/"ds"xx"ds"/"dt"="v""dV"/"ds"`

So, a = v`"dv"/"ds"`

= 20 × 5

= 100 m/sec².