Question

A particle of mass 4M at rest disintegrates into two particles of mass M and 3M respectively having non zero velocities. The ratio of de-Broglie wavelength of particle of mass M to that of mass 3M will be:

पर्याय

• 1 : 3

• 3 : 1

• 1 : `sqrt3`

• 1 : 1

Answer 1

1 : 1

Explanation:

de-Broglie wavelength, λ = `"h"/"P"`

In this case, the momentum of both mass particles is the same. 3 m and m, or the de-Broglie wavelength ratio,

`lambda_(2"m")/lambda_"m"=1/1`