Question

A particle of mass m and charge q is moving with velocity `vecv = v_xhati + v_yhatj`. If it is subjected to a magnetic field `vecB = B_0hati`, it will move in a ______.

पर्याय

• straight line path 

• circular path

• helical path 

• parabolic path

Answer 1

A particle of mass m and charge q is moving with velocity `vecv = v_xhati + v_yhatj`. If it is subjected to a magnetic field `vecB = B_0hati`, it will move in a helical path.

Explanation:

We will examine the velocity of a charged particle in a uniform magnetic field. The velocity component along B remains unaffected by the magnetic field. Motion in a plane perpendicular to B is, as opposed to a circular one, results in helical motion.