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प्रश्न
A particle of mass 'm' having charge 'q' is held at rest in uniform electric field of intensity 'E'. When it is released, the kinetic energy attained by it after covering a distance 'y' will be ______.
पर्याय
`"mE"/"q"`y
Eqy
`"mqy"/"E"`
mEqy
MCQ
रिकाम्या जागा भरा
उत्तर
A particle of mass 'm' having charge 'q' is held at rest in uniform electric field of intensity 'E'. When it is released, the kinetic energy attained by it after covering a distance 'y' will be Eqy.
Explanation:
F = qE ∴ a = `"qE"/"m"`
a = `"dV"/"dt" = "dV"/"ds" * "ds"/"dt" = "V" "dV"/"ds"`
`therefore "VdV" = "qE"/"m"`ds
`"V"^2/2 = "qE"/"m"`y
`therefore "V"^2 = "qE"/"m"`y
`"E" = 1/2 "mV"^2 = 1/2 "m" "qE"/"m"`y = qEy
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