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प्रश्न
A particle performs S.H.M. Its potential energies are 'U1' and 'U2' at displacements 'x1' and 'x2' respectively. At displacement (x1 + x2), its potential energy 'U' is ______.
पर्याय
`sqrtU=(sqrtU_1+sqrtU_2)^2`
`sqrtU=(sqrtU_1-sqrtU_2)^2`
`sqrtU=sqrtU_1+sqrtU_2`
`sqrtU=sqrtU_1-sqrtU_2`
MCQ
रिकाम्या जागा भरा
उत्तर
A particle performs S.H.M. Its potential energies are 'U1' and 'U2' at displacements 'x1' and 'x2' respectively. At displacement (x1 + x2), its potential energy 'U' is `underline(sqrtU=sqrtU_1+sqrtU_2)`.
Explanation:
`U_1=1/2kx_1^2` `thereforex_1=sqrt((2U_1)/"k")`
`U_2=1/2kx_2^2` `thereforex_2=sqrt((2U_2)/"k")`
`therefore U=1/2k(x_1+x_2)^2`
`thereforex_1+x_2=sqrt((2U)/"k")`
`sqrt((2U_1)/"k")+sqrt((2U_2)/"k")=sqrt((2U)/"k")`
`thereforesqrtU=sqrtU_1+sqrtU_2`
shaalaa.com
The Energy of a Particle Performing S.H.M.
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