Advertisements
Advertisements
प्रश्न
A permanent magnet in the shape of a thin cylinder of length 10 cm has M = 106 A/m. Calculate the magnetisation current IM.
उत्तर
According to the problem, M (intensity of magnetisation) = 106 A/m.
`l`(length) = 10 cm = 10 × 10–2 m = 0.1 m
And IM = magnetisation current
Here we know that M = `I_M/l`
⇒ IM = M x `l`
= 106 × 0.1 = 105 A
Important point: Here, M = Intensity of magnetisation as its units are given as A/m.
APPEARS IN
संबंधित प्रश्न
Which of the following substances are diamagnetic?
Bi, Al, Na, Cu, Ca and Ni
Draw magnetic field line when a (i) diamagnetic, (ii) paramagnetic substance is placed in an external magnetic field. Which magnetic property distinguishes this behaviour of the field line due to the substances?
The magnetic susceptibility of platinum is 0.0001. It's relative permeability is:
The earth’s field departs from its dipole shape substantially at large distances (greater than about 30,000 km). What agencies may be responsible for this distortion?
Which graph shows the variation of magnetic susceptibility (`chi`) with magnetizing field (H) for a paramagnetic substance?
Would the maximum possible magnetisation of a paramagnetic sample be of the same order of magnitude as the magnetisation of a ferromagnet?
The magnetic susceptibility for diamagnetic materials is ______.
- Assertion (A): Diamagnetic substances exhibit magnetism.
- Reason (R): Diamagnetic materials do not have a permanent magnetic dipole moment.
State the dimensions of magnetization.
Magnetic susceptibility of a diamagnetic substance ______.