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प्रश्न
A piece of lead weighing 500 g gives out 1200 calories of heat when it is cooled from 100° C to 20° C. Find its specific heat.
पर्याय
0.003 cal/g° C
0.033 cal/g° C
0.03 cal/g° C
0.3 cal/g° C
MCQ
उत्तर
0.03 cal/g° C
Explanation:
`"c" = "Q"/("m" Delta"T")`
`= 1200/(500 xx (90 - 10))`
`= 0.03 "cal/g° C"`
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