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A piece of metal weighs 44.5 gf in air, 39.5 gf in water. What is the R.D. of the metal? - Physics

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प्रश्न

A piece of metal weighs 44.5 gf in air, 39.5 gf in water. What is the R.D. of the metal?

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उत्तर

Piece of metal weighs in air = 44.5 f
Piece of metal weighs in liquid = 39.5 f.
Loss of weight of metal in liquid = 44.5 - 39.5 = 5f.
Relative density = weight of solid in air/ loss of weight of solid in water.
Relative density of liquid =44.5f/5f =8.9
Relative density of liquid = 8.9

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Determination of Relative Density of a Solid Substance by Archimedes’ Principle
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Fluids - Exercise 3 [पृष्ठ १७८]

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फ्रँक Physics [English] Class 9 ICSE
पाठ 4 Fluids
Exercise 3 | Q 36 | पृष्ठ १७८
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