मराठी

A Piece of Wax Floats on Brine. What Fraction of Its Volume is Immersed? Density of Wax = 0.95 G Cm-3, Density of Brine = 1.1 G Cm-3. - Physics

Advertisements
Advertisements

प्रश्न

A piece of wax floats on brine. What fraction of its volume is immersed?

Density of wax = 0.95 g cm-3, Density of brine = 1.1 g cm-3. 

बेरीज

उत्तर

Density of wax (`ρ_"w"`) = `0.95  "gcm"^-3`

Density of brine (`ρ_"B"`) = `1.1  "gcm"^-3`

Let the total volume of piece of wax be V and the volume of immersed portion be v .

According to the law of floatation , 

`"v"/"V" = ρ_"w"/ρ_"B"`

or , `"v"/"V" = 0.95/1.1 = 0.86`

or , v = 0.86 V

Thus , wax floats with 0.86th part of its volume above the surface brine . 

shaalaa.com
Relation Between Volume of Submerged Part of a Floating Body, the Densities of Liquid and the Body
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Upthrust in Fluids, Archimedes’ Principle and Floatation - Exercise 5 (C) [पृष्ठ १२४]

APPEARS IN

सेलिना Concise Physics [English] Class 9 ICSE
पाठ 5 Upthrust in Fluids, Archimedes’ Principle and Floatation
Exercise 5 (C) | Q 4 | पृष्ठ १२४

संबंधित प्रश्‍न

A body of volume 100 cm3 weighs 5 kgf in air. It is completely immersed in a liquid of density 1.8 × 103 kg m-3. Find:

  1. The upthrust due to liquid and
  2. The weight of the body in liquid. 

A loaded cargo ship sails from sea water to river water. State and Explain your observations. 


If the density of ice is 0.9 g cm-3, then what portion of an iceberg will remain below the surface of water in sea? (Density of sea water = 1.1 g cm-3) 


A wooden block floats in water with two-third of its volume submerged.
(a) Calculate the density of wood. 
(b) When the same block is placed in oil, three-quarters of its volume is immersed in oil. Calculate the density of oil.
 


When a piece of ice floating in water melts, the level of water inside the glass remains same. Explain.


A body of mass 50 g is floting in water. What is the apparent weight of body in water? Explain your answer.


A body weighs 300 gf in air and 280 gf when completely immersed in water. Calculate:
(i) The loss in weight of the body,
(ii) The upthrust on the body.


When a piece of wood is suspended from the hook of a spring balance, it reads 90 gf. The wood is now lowered into the water. What reading do you expect on the scale of the spring balance?

A wooden cube of side 10 cm has a mass of 700 g. It will float in the water with:
(a) Half of its volume inside the water
(b) 3 cm height above the water surface
(c) 7 cm height above the water surface
(d) Just inside the water surface.


Complete the following result:

Mass = _______ × density


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×