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प्रश्न
A point A is 26 cm away from the centre of a circle and the length of the tangent drawn from A to the circle is 24 cm. Find the radius of the circle.
पर्याय
`2sqrt313`
12
7
10
MCQ
रिकाम्या जागा भरा
उत्तर
10
Explanation:
Let O be the centre of the circle and let A be a point outside the circle such that OA = 26 cm.
Let AT be the tangent to the circle.
Then, AT = 24 cm. Join OT.
Since the radius through the point of contact is perpendicular to the tangent, we have ∠OTA = 90°. In right ΔOTA, we have
OT2 = OA2 - AT2
= [(26)2 - (24)2] = (26 + 24) (26 - 24) = 100.
⇒ OT = `sqrt100` = 10 cm
Hence, the radius of the circle is 10 cm.
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