Advertisements
Advertisements
प्रश्न
A proton and a deuteron are accelerated through the same accelerating potential. Which one of the two has less momentum?
Give reasons to justify your answer.
उत्तर
Momentum
`p=h/lambda`
or `pprop1/lambda`
where, h = plank's constant
As the wavelength of a proton is more than that of deutron thus, the momentum of a proton is lesser than that of deutron. Hence, the momentum of proton is less.
APPEARS IN
संबंधित प्रश्न
The energy of photon of wavelength X is_____ .
[h = Planck’s constant, c = speed of light in vacuum]
The threshold wavelength of silver is 3800Å. Calculate the maximum kinetic energy in eV of photoelectrons emitted, when ultraviolet light of wavelength 2600Å falls on it.
(Planck’s constant, h =6.63 x 1O-34J.s.,
Velocity of light in air, c = 3 x 108 m / s)
State two important properties of photon which are used to write Einstein’s photoelectric equation.
Einstein's photoelectric equation is:
a) `E_"max" = hlambda - varphi_0`
b) `E_"max"= (hc)/lambda varphi_0`
c) `E_"max" = hv + varphi_0`
d) `E_"max" = (hv)/lambda + varphi_0`
According to Einstein’s model minimum energy needed for the electron to escape from a metal surface having work function ϕ0, the electron is emitted with maximum kinetic energy, Kmax = ______.
Plot a labelled graph of |Vs| where Vs is stopping potential versus frequency f of the incident radiation. State how will you use this graph to determine the value of Planck's constant?
In an inelastic collision, which of the following does not remain conserved?
Radiations of two photon's energy, twice and ten times the work function of metal are incident on the metal surface successively. The ratio of maximum velocities of photoelectrons emitted in two cases is:
A 200 W sodium street lamp emits yellow light of wavelength 0.6 µm. Assuming it to be 25% efficient in converting electrical energy to light, the number of photons of yellow light it emits per second is:
If the frequency of light in a photoelectric experiment is double the stopping potential will
