मराठी

A racing car is travelling along a track at a constant speed of 40 m/s. A T.V. cameraman is recording the event from a distance of 30 m directly away from the track as shown in the figure. -

Advertisements
Advertisements

प्रश्न

A racing car is travelling along a track at a constant speed of 40 m/s. A T.V. cameraman is recording the event from a distance of 30 m directly away from the track as shown in the figure. In order to keep the car under view in the position shown, the angular speed with which the camera should be rotated is ______.

 

पर्याय

  • `4/3` rad/s

  • `3/4` rad/s

  • `8/3sqrt3` rad/s

  • 1 rad/s

MCQ
रिकाम्या जागा भरा

उत्तर

A racing car is travelling along a track at a constant speed of 40 m/s. A T.V. cameraman is recording the event from a distance of 30 m directly away from the track as shown in the figure. In order to keep the car under view in the position shown, the angular speed with which the camera should be rotated is 1 rad/s.

Explanation:

We have

tan θ = `x/30; "d"/"dt" [tan theta] = "d"/"dt" [x/30]`

`"d"/("d"theta)(tan theta).("d"theta)/"dt" = 1/30 "dx"/"dt"`

sec2θ `("d"theta)/"dt" = 1/30xx40`

⇒ `("d"theta)/"dt" = 4/(3sec^2theta)`

At the given instant, θ = 30°

⇒ `ω = ("d"theta)/"dt" = 4/3` cos230°

= `4/3xx(sqrt3/2)^2`

= `4/3xx3/4`

= 1 rad s-1

or the angular speed with which the camera should be rotated = 1 rad/s.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×