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प्रश्न
A radioactive isotope decayed to 17/32 of its original mass after 60 minutes. Find the half-life of this radioisotope.
पर्याय
65 minutes
67 minutes
66 minutes
68 minutes
MCQ
उत्तर
66 minutes
Explanation:
The half-life of radioactive isotope is
`17/32 = 0.53125`
`(1/2)^"n" = 0.53125`
n log 0.5 = log 0.53125
n = 0.91254
60 minutes divided by 0.91254 equals 65.75 minutes. Therefore, n = 66 minutes.
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