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प्रश्न
A ray of light is incident on a water surface of refractive index `4/3` making an angle of 40° with the surface. Find the angle of refraction.
संख्यात्मक
उत्तर
`n=4/3`, i = 90° - 40° = 50°
`n = sini/sinr`
`sinr=sini/n`
`=(sin50°)/(4/3)`
`=0.7660/(4/3)`
`=0.5745`
The angle of refraction,
r = sin-1(0.5745) = 35°4'
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