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प्रश्न
A rectangular block of mass 'm' and cross-sectional area 'A' floats on a liquid of density ρ. If it is given a small vertical displacement from equilibrium, it starts oscillating with frequency 'n' equal to ______.
(g = acceleration due to gravity)
पर्याय
`2pisqrt("m"/(Arhog))`
`1/(2pi)sqrt((Arhog)/"m")`
`2pisqrt((Arhog)/"m")`
`1/(2pi)sqrt("m"/(Arhog))`
उत्तर
A rectangular block of mass 'm' and cross-sectional area 'A' floats on a liquid of density ρ. If it is given a small vertical displacement from equilibrium, it starts oscillating with frequency 'n' equal to `underline(1/(2pi)sqrt((Arhog)/"m"))`.
Explanation:
`T=2pisqrt(l/g)` l = length of block dipped in liquid
Now, mg = Alρg
`l="m"/(Arho)`
`T=2pisqrt("m"/(Arhog))`
`thereforen=1/T=1/(2pi)sqrt((Arhog)/"m")`