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प्रश्न
A rectangular loop of sides 8 cm and 2 cm with a small cut is stationary in a uniform magnetic field directed normal to the loop. The magnetic field is reduced from its initial value of 0.3 T at the rate of 0.02 T s-1 If the cut is joined and loop has a resistance of 1.6 Ω, then how much power is dissipated by the loop as heat?
पर्याय
6.2 × 10-10 W
6.1 × 10-10 W
6.3 × 10-10 W
6.4 × 10-10 W
MCQ
उत्तर
6.4 × 10-10 W
Explanation:
A = 8 × 2 = 16 sq cm = 16 × 10-4 m-2
`"dB"/"dt" = - 0.02 " Ts"^-1`
∴ Induced emf e = `- ("d"phi)/"dt" = "AdB"/"dt"`
`= - 16 xx 10^-4 (- 0.02) = 32 xx 10^-6 "V"`
Power loss = `"e"^2/"R" => (32 xx 10^-6)^2/1.6`
P = `(32 xx 10^-6 xx 32 xx 10^-6)/1.6`
P = 64 × 10-11
P = 6.4 × 10-10 W
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