Question

A sample of calcium carbonate has the following percentage composition.

Ca = 40%, C = 12% and O = 48%

According to law of definite proportion the weight of calcium in 4 g of a sample of calcium carbonate from another source will be (At. No.: Ca = 40, C = 12, O = 16)

पर्याय

• 1.6 g

• 1.6 × 10^-2 g

• 0.1 g

• 0.2 g

Answer 1

1.6 g

Explanation:

In 100 g of CaCO₃, 40 g Ca is present

∴ In 4 g of CaCO₃ = `(4 xx 40)/100` = 1.6 g of Ca is present.