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प्रश्न
A set of 25 tuning forks is arranged in order of decreasing frequencies. Each fork produces 3 beats with succeeding one. If the first fork is octave of last, then the frequency of 1st and 15th fork in Hz is ______.
पर्याय
144, 99
72, 99
144, 102
72, 102
MCQ
रिकाम्या जागा भरा
उत्तर
A set of 25 tuning forks is arranged in order of decreasing frequencies. Each fork produces 3 beats with succeeding one. If the first fork is octave of last, then the frequency of 1st and 15th fork in Hz is 144, 102.
Explanation:
n1 - n2 = 3 ∴ n1 - n2 = - 3
n2 - n3 = 3 n3 = n2 - 3 = n1 - 6 = n1 - 2 · 3 = n1 - (3 - 1) · 3
n25 = n1 - (25 - 1) · 3
`"n"_1/2 = "n"_1 - 72`
∴ n1 = 72 × 2 = 144 Hz
n15 = 144 - 14.3 = 144 - 42 = 102 Hz
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