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प्रश्न
A simple harmonic motion is given by, x = 2.4 sin ( 4πt). If distances are expressed in cm and time in seconds, the amplitude and frequency of S.H.M. are respectively,
पर्याय
1.2 cm, 2 Hz
2.4 cm, 2 Hz
1.2 cm, 1 Hz
2.4 cm, 1 Hz
MCQ
उत्तर
2.4 cm, 2 Hz
Explanation:
x = 2.4 sin ( 4πt)
Comparing with x = A sin ωt, we get
A = 2.4 cm, ω = 4π
∴ 2πn = 4π or n = 2 Hz
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