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प्रश्न
A small cyclotron of maximum radius 0.5 m accelerates protons in a 1.7 T magnetic field. Calculate the kinetic energy (maximum) of protons when they leave the cyclotron.
संख्यात्मक
उत्तर
Given: B = 1.7 T, q = 1.6 x 10-19 C, m = 1.66 x 10-27 kg, rmax = 0.5 m
`KE_max=(q^2B^2)/(2m)r_max^2`
`KE_max=((1.6xx10^-19)xx1.7xx1.7xx0.5xx0.5)/(2xx1.66xx10^-27)`
`=(1.8496xx10^-38)/(3.32xx10^-27)`
`=0.5571xx10^-11`
`KE_max=5.5xx10^-12J`
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Cyclotron Motion
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