Question

A small loop of area of cross-section 10^-6 m² is lying concentrically and coplanar inside a bigger loop of radius 0.628 m. A current of 20 A is passed in the bigger loop. The smaller loop is rotated about its diameter with an angular velocity `omega`. The magnetic flux linked with the smaller loop will be ____________.

पर्याय

• 2 x 10^-11 sin `omega"t"`

• 2 x 10^-11 cos `omega"t"`

• 2 x 10^-9 sin `omega"t"`

• 2 x 10^-9 cos `omega"t"`

Answer 1

A small loop of area of cross-section 10^-6 m² is lying concentrically and coplanar inside a bigger loop of radius 0.628 m. A current of 20 A is passed in the bigger loop. The smaller loop is rotated about its diameter with an angular velocity `omega`. The magnetic flux linked with the smaller loop will be `underline(2xx10^-11cosomega"t")`

Explanation:

`phi = "BA cos"  omega"t"`

` = (mu_0  "IA")/(2  "R")  "cos"  omega "t"`

`= (4 xx 3.14 xx 10^-7 xx 20 xx 10^-6)/(2 xx 0.628)  "cos"  omega"t"`

`= 2 xx 10^-11  "cos"  omega"t"`