Question

A solid compound XY has Nacl structure. If the radium of cation (X⁺) is 100 pm, the radium of anion (r^–) will be:-

पर्याय

• 275.1 pm

• 322.5 pm

• 241.5 pm

• 165.7 pm

Answer 1

In NaCl coordination number of each type of ion in solid is 6 and radius ratio is `r^+/r^-` = 0.414.

Given the radius of cation r⁺ = 100 pm.

So, radius of anion r^– = `100/0.414` = 241.5 pm.