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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

A solution containing 3 g of solute A (M = 60 g/mol) in 1 L solution is isotonic with a solution containing 8.55 g of solute B in 500 mL solution. What is the molar mass of B? - Chemistry

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प्रश्न

A solution containing 3 g of solute A (M = 60 g/mol) in 1 L solution is isotonic with a solution containing 8.55 g of solute B in 500 mL solution. What is the molar mass of B?

संख्यात्मक

उत्तर

Given: Mass of solute A = (W2)A = 3 g
Volume = VA = 1 L
Molar mass of solute A = (M2)A = 60 g mol−1
Mass of solute B = (W2)B = 8.55 g
Volume = VB = 500 mL = 0.5 L

To find: Molar mass of solute B = (M2)B

Formula: π = `("W"_2"RT")/("M"_2"V")`

Calculation: For solution containing 3 g of solute A,

`pi_"A" = (("W"_2)_"A""RT")/(("M"_2)_"A" "V"_"A")`    .....(i)

For solution containing 8.55 g of solute B,

`pi_"B" = (("W"_2)_"B""RT")/(("M"_2)_"B" "V"_"B")`    .....(ii)

Since both the solutions are isotonic, πA = πB

∴ `(("W"_2)_"A""RT")/(("M"_2)_"A" "V"_"A") = (("W"_2)_"B""RT")/(("M"_2)_"B" "V"_"B")`

∴ `("M"_2)_"B" = (("W"_2)_"B" xx ("M"_2)_"A" xx "V"_"A")/(("W"_2)_"A" xx "V"_"B")`

`= (8.55 xx 60 xx 1)/(3 xx 0.5)` = 342 g mol-1

The molar mass of solute B is 342 g mol−1

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