Question

A steady current of 1 A is flowing through the conductor. The number of electrons flowing through the cross-section of the conductor in 1 second is ______

पर्याय

• 6.25 × 10¹⁵

• 6.25 × 10¹⁷

• 6.25 × 10¹⁹

• 6.25 × 10¹⁸

Answer 1

A steady current of 1 A is flowing through the conductor. The number of electrons flowing through the cross-section of the conductor in 1 second is 6.25 × 10¹⁸.

Explanation:

q = It ⇒ ne = It

∴ n = `"It"/"e" = (1 xx 1)/(1.6 xx 10^-19)`

= 6.25 × 10¹⁸