Question

A stone of mass 1 kg is rotated in a horizontal circle of radius 0.5 m. If it makes `100/pi` rps, then its angular momentum is ______

पर्याय

• 50 kg m² s^-1

• 2.5 x 10^-3 kg m² s^-1

• 5π² x 10^-3 kg m² s^-1

• 800 kg m² S^-1 

Answer 1

A stone of mass 1 kg is rotated in a horizontal circle of radius 0.5 m. If it makes `100/pi` rps, then its angular momentum is 50 kg m² s^-1.

Explanation:

I = `MR^2 = 1 xx (0.5)^2 = 0.25` kg m²

∴ `omega = 2pin = 2 xx pi xx 100/pi = 200` rad/s

∴ L = `Iomega = 0.25 xx 200 = 50` kg m²/s.