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प्रश्न
A stretched wire 60 cm long is vibrating with its fundamental frequency of 256 Hz. If the length of the wire is decreased to 15 cm and the tension remains the same. Then the fundamental freuqency of the vibration of the wire will be ______.
पर्याय
1024
572
256
64
MCQ
रिकाम्या जागा भरा
उत्तर
A stretched wire 60 cm long is vibrating with its fundamental frequency of 256 Hz. If the length of the wire is decreased to 15 cm and the tension remains the same. Then the fundamental freuqency of the vibration of the wire will be 1024.
Explanation:
L0 = 60 cm v0 = 256 Hz
v = `1/(2"L")sqrt("T"/"m")` ∴ v ∝ `1/"L"`
`"v"_1/"v"_0="L"_0/"L"_1`
⇒ v1 = `"v"_0"L"_0/"L"_1`
= `256xx60/15`
= 1024 Hz.
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