मराठी

A student argues that ‘there are 11 possible outcomes 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12. Therefore, each of them has a probability 1/11 - Mathematics

Advertisements
Advertisements

प्रश्न

 A student argues that ‘there are 11 possible outcomes 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12. Therefore, each of them has a probability 1/11. Do you agree with this argument?

उत्तर

Probability of each of these sums will not be 1/11 as these sums are not equally likely.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 15: Probability - Exercise 15.1 [पृष्ठ ३१०]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 10
पाठ 15 Probability
Exercise 15.1 | Q 22.2 | पृष्ठ ३१०
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×