Question

A uniform electric field of intensity 400 N/C, exists in a certain region. How much flux will cross a given area of 10 cm² in this region, if the area vector is inclined at 60° to the direction of the field?

पर्याय

• 0.1 Nm²/C

• 0.2 Nm²/C

• 0.5 Nm²/C

• 2 Nm²/C

Answer 1

0.2 Nm²/C

Explanation:

`phi=vec"E"*vec"A"="E"  "A"costheta`

`=400xx10xx10^-4xx1/2=0.2` Nm²/C