Advertisements
Advertisements
प्रश्न
A vessel contains water up to a height of 1.5 m. Taking the density of water 103 kg m-3, acceleration due to gravity 9.8 m s-2 and area of base of vessel 100 cm2, calculate: (a) the pressure and (b) the thrust at the base of vessel.
उत्तर
Given height , h = 1.5 m
Density of water , ρ = 103 kgm-3
Acceleration due to gravity , g = 9.8 m/s2
Area of base of the vessel , a = 100 cm2 = `100 xx 10^-4 "m"^2`
(a) Pressure , P = hρg
or , P = `1.5 xx 10^3 xx 9.8`
or , P = `1.47 xx 10^4 "Nm"^-2`
(b) Thrust = Pressure × area
or , thrust = `1.47 × 10^4 × 100 × 10^-4` N
or , thrust = 147 N
APPEARS IN
संबंधित प्रश्न
An object of weight 200 N is floating in a liquid. What is the magnitude of buoyant force acting on it ?
A body experiences the same buoyant force when it floats or sinks in water.
Name the S.I. unit of density. How is it related to g Cm-3?
Explain why an iron needle sinks in water, but a ship made of iron floats on water.
For a given object, the buoyant force in liquids of different ______ is ______.
Complete the following sentence :
Pressure at all points at the same depth is ....................
A small block of wood is completely immersed in (i) water, (ii) glycerine and then released. In each case, What do you observe? Explain the difference in your observation in the two cases.
A beaker contains a liquid of density ‘ρ’ up to height ‘h’ such that ‘PA’ is atmospheric pressure and ‘g’ is the acceleration due to gravity. Answer the following questions:
- What is the pressure on the free surface of the liquid?
- What is the pressure on the base of the beaker?
- What is the lateral pressure at the base on the inner walls of the beaker?
How is thrust different from pressure?
The point at which the force of buoyancy is supposed to act is known as ______.